Group properties forced by literal commutator relators
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Must a one-relator group whose relator is literally a commutator be Hopfian, residually finite or automatic? These are separate properties, and a literal commutator is more restrictive than an arbitrary element of the free group’s commutator subgroup.
Why it matters and what counts as progress
Why it matters: Literal commutator relators are a narrower condition than membership in a commutator subgroup, so earlier broader counterexamples do not suffice.
What counts as progress: Prove one of the three properties under additional hypotheses or give explicit commutator-relator groups where it fails.
How the problem developed
- 1999 · Open problem [1]
Gilbert Baumslag Asked whether one-relator groups whose relator lies in the commutator subgroup must be Hopfian, residually finite, or automatic.
- 23 Jul 2026 · Counterexample family [2]
Ke Wang and Qiang Zhang Constructed commutator-relator one-relator groups answering all three questions negatively, including literal relators of the form [u,v]; earlier work had already answered residual finiteness and automaticity negatively for the broader commutator-subgroup case.
AI contribution
Commutator relators of one-relator groups do not force Hopficity, residual finiteness, or automaticity
For G_m=⟨a,t | [t,a[a,t]^(−m)]⟩, a Baumslag–Solitar group BS(m,m+1) is a retract. In particular, G_2 is non-Hopfian and non-residually finite, while G_1 is non-automatic. Literal commutator relators therefore do not force any of these properties.
Sources
- Baumslag, Myasnikov, and Shpilrain, Open problems in combinatorial group theory, second edition
- Wang and Zhang, Commutator relators of one-relator groups do not force Hopficity, residual finiteness, or automaticity
- Wang and Zhang, Commutator relators of one-relator groups do not force Hopficity, residual finiteness, or automaticity
Website timeline
Publication dates and editorial changes.
ChatGPT-assisted group examples answer three Baumslag questions