OpenAI reports the unique SU(N) BFSS threshold state

For every finite N≥2, the undeformed SU(N) BFSS matrix quantum-mechanics Hamiltonian after removal of center-of-mass coordinates has exactly one normalizable zero-energy state.

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Understanding the problem

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For every finite N≥2, the undeformed SU(N) BFSS matrix quantum-mechanics Hamiltonian after removal of center-of-mass coordinates has exactly one normalizable zero-energy state.

Why it matters

If correct, resolves the BFSS threshold-bound-state conjecture for all finite N.

What counts as progress

Does SU(N) BFSS matrix quantum mechanics have exactly one normalizable zero-energy state?

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