OpenAI reports zero-plane rigidity for Einstein four-manifolds

Every connected closed Einstein four-manifold with positive Einstein constant and nonnegative sectional curvature that has even one zero-curvature two-plane has universal Riemannian cover isometric to a product of two equal-radius round two-spheres.

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Understanding the problem

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Every connected closed Einstein four-manifold with positive Einstein constant and nonnegative sectional curvature that has even one zero-curvature two-plane has universal Riemannian cover isometric to a product of two equal-radius round two-spheres.

Why it matters

If correct, determines the boundary case of the nonnegative sectional-curvature classification.

What counts as progress

Does one zero-curvature plane force product geometry in a nonnegatively curved Einstein four-manifold?

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