OpenAI reports the sharp terminal leave in random triangle removal
- Mathematics
For random triangle removal from Kₙ, the number of edges left at termination divided by n^(3/2) converges in L² to 1/(2√2).
OpenAI reports the sharp terminal leave in random triangle removal
- Mathematics
For random triangle removal from Kₙ, the number of edges left at termination divided by n^(3/2) converges in L² to 1/(2√2).
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Read the background
For random triangle removal from Kₙ, the number of edges left at termination divided by n^(3/2) converges in L² to 1/(2√2).
Why it matters
If correct, proves the sharp terminal-leave constant for the triangle-removal process.
What counts as progress
What is the sharp terminal number of edges in random triangle removal?
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OpenAI reports the sharp terminal leave in random triangle removal