OpenAI reports that mixing implies all finite orders of mixing

Every invertible mixing probability-preserving transformation is mixing of every finite order: for any k≥3 measurable sets, their translated intersection tends to the product of their measures as successive time gaps diverge.

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Understanding the problem

Read the background

Every invertible mixing probability-preserving transformation is mixing of every finite order: for any k≥3 measurable sets, their translated intersection tends to the product of their measures as successive time gaps diverge.

Why it matters

If correct, answers Rokhlin’s longstanding multiple-mixing problem for a single invertible transformation.

What counts as progress

Does ordinary mixing of one invertible transformation imply mixing of every finite order?

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