OpenAI reports single-fold Diophantine representations

Every recursively enumerable subset of natural-number n-tuples, for n≥1, has an integer-polynomial Diophantine representation with exactly one complete natural-number auxiliary tuple for each member and none for nonmembers.

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Understanding the problem

Read the background

Every recursively enumerable subset of natural-number n-tuples, for n≥1, has an integer-polynomial Diophantine representation with exactly one complete natural-number auxiliary tuple for each member and none for nonmembers.

Why it matters

If correct, resolves the single-fold conjecture and therefore the finite-fold conjecture for recursively enumerable sets.

What counts as progress

Does every recursively enumerable set have a one-witness Diophantine representation?

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