For integers b,c≥2, the Stoneham number α(b,c)=Σ_{k≥1}1/(c^k b^{c^k}) is normal in base b exactly when some prime divisor of c does not divide b.
For integers b,c≥2, the Stoneham number α(b,c)=Σ_{k≥1}1/(c^k b^{c^k}) is normal in base b exactly when some prime divisor of c does not divide b. In particular α(6,4) is not 6-normal despite neither parameter dividing the other.
For integers b,c≥2, the Stoneham number α(b,c)=Σ_{k≥1}1/(c^k b^{c^k}) is normal in base b exactly when some prime divisor of c does not divide b. In particular α(6,4) is not 6-normal despite neither parameter dividing the other.
If correct, settles the Bailey–Crandall extension question and gives the exact normality criterion.
When is a Stoneham number normal in its defining base beyond the coprime parameter case?
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